H2(g) + I2(g) 2 HI(g) Kc = 55.3

[H2] = [I2] = 1.00 - x = 0.21 M

[HI] = 2x = 1.58 M

Step 3. Solve for x. 55.3 = (2x)2/(1-x)2

In this case, take square root of both sides.

Solution gives: x = 0.79

Therefore, at equilibrium

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